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		<title>Inequality 15</title>
		<link>http://mathsmaster.wordpress.com/2009/04/07/inequality-15/</link>
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		<pubDate>Tue, 07 Apr 2009 19:10:55 +0000</pubDate>
		<dc:creator>mathsmaster</dc:creator>
				<category><![CDATA[Inégalités]]></category>

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		<description><![CDATA[Problem: let  be positive reel numbers; Prove that: Solution: assuming that,   we get ,     then by Chebychev, and by Cauchy-Scwarz tow times, then<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=mathsmaster.wordpress.com&amp;blog=6029773&amp;post=141&amp;subd=mathsmaster&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Problem:</strong> let <span class="postbody"><img class="latex" style="vertical-align:-4px;" title="a,b,c" src="http://alt2.mathlinks.ro/latexrender/pictures/9/c/a/9caa91157421e243281346b0bf7a82b5200e67e2.gif" alt="" /> be positive reel numbers; Prove that:</span></p>
<p style="text-align:center;"><span class="postbody"><span class="postbody"><img class="latex" style="vertical-align:-15px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/d/1/0/d1053b73125c44eaf86e573d1cca5c6317ece229.gif" alt="\frac{a}{(b+c)^2}+\frac{b}{(a+c)^2}+\frac{c}{(a+b)^2}\geq \frac{9}{4(a+b+c)}" /></span></span></p>
<p><strong>Solution:</strong> assuming that,  <span class="postbody"><img class="latex" style="vertical-align:-3px;" title="a \geq b \geq c" src="http://alt1.mathlinks.ro/latexrender/pictures/5/6/a/56a9a53cac60e119936e5698f2521bddcd6db90d.gif" alt="" /> we get ,</span></p>
<p><span class="postbody"><img class="latex" style="vertical-align:-16px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/7/c/a/7ca299a498b1d83e49659ff91654aca043a69bcc.gif" alt="\frac{1}{(b+c)^2} \geq \frac{1}{(c+a)^2} \geq \frac{1}{(a+b)^2}" />    then by Chebychev,</span></p>
<p><span class="postbody"><img class="latex" style="vertical-align:-17px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/5/0/8/508aa57fd398935b3a1332cfd913dfe8d551d362.gif" alt="S=\sum \frac{a}{(b+c)^2}\geq \frac{1}{3}(a+b+c)\left(\sum\frac{1}{(a+b)^2}\right)" /></span></p>
<p><span class="postbody">and by Cauchy-Scwarz tow times,</span></p>
<p><span class="postbody"><img class="latex" style="vertical-align:-17px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/c/6/5/c65dd1b5f8655f1116a4cd13b230a5f85e97a255.gif" alt="\sum \frac{1}{(a+b)^2}\geq \frac{1}{3}\left(\frac{1}{a+b}\right)^2\geq \frac{1}{3}\left(\frac{9}{2(a+b+c)}\right)^2" /></span></p>
<p><span class="postbody">then <img class="latex" style="vertical-align:-22px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/1/5/0/150f07bb3cfd4d162f7361a968fa465ae40abb30.gif" alt="S\geq \frac{1}{3}(a+b+c)\left(\frac{1}{3}\left(\frac{9}{2(a+b+c)}\right)^2\right)=\frac{9}{4(a+b+c)}" /></span></p>
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		<title>Inequality 14</title>
		<link>http://mathsmaster.wordpress.com/2009/04/07/inequality-14-2/</link>
		<comments>http://mathsmaster.wordpress.com/2009/04/07/inequality-14-2/#comments</comments>
		<pubDate>Tue, 07 Apr 2009 18:47:19 +0000</pubDate>
		<dc:creator>mathsmaster</dc:creator>
				<category><![CDATA[Inégalités]]></category>

		<guid isPermaLink="false">http://mathsmaster.wordpress.com/?p=139</guid>
		<description><![CDATA[Problem: let   be a positive reel numbers such as,   . Prove that; Ukraine, 2001 Solution: we can rewrite the inequality as: or again , assume that                and      , we get that    then by Chebychev,      (*) and we have that,   and     then,   from (*) and (**) we deduct [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=mathsmaster.wordpress.com&amp;blog=6029773&amp;post=139&amp;subd=mathsmaster&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Problem:</strong> let <span class="postbody"><img class="latex" style="vertical-align:-4px;" title="a,b,c,x,y,z" src="http://alt2.mathlinks.ro/latexrender/pictures/b/c/d/bcdfe3660e8e129e0815cea864f799b98f2b833d.gif" alt="" />  be a positive reel numbers such as, <img class="latex" style="vertical-align:-4px;" title="x+y+z=1" src="http://alt1.mathlinks.ro/latexrender/pictures/7/0/b/70bd89f5cb028738daf11d0051c45b656f044c22.gif" alt="" />  . Prove that;</span></p>
<p><span class="postbody"><img class="latex" style="vertical-align:-5px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/9/d/d/9ddd4b061270b53b97115475af94b348994b43ae.gif" alt="ax+by+cz+2\sqrt{(xy+yz+zx)(ab+bc+ca)}\leq a+b+c" /></span></p>
<p style="text-align:center;"><span class="postbody">Ukraine, 2001</span></p>
<p><span class="postbody"><strong>Solution: </strong>we can rewrite the inequality as:</span></p>
<p><span class="postbody"><span class="postbody"><img class="latex" style="vertical-align:-5px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/e/2/a/e2af0521c7cc7eae2e53064196c557986ac3ce97.gif" alt="2\sqrt{(xy+yz+zx)(ab+bc+ca)}\leq a(1-x)+b(1-y)+c(1-z)" /></span></span></p>
<p><span class="postbody"><span class="postbody">or again ,<img class="latex" style="vertical-align:-5px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/8/e/5/8e57c1f45de9cb956297ce3d3ba421b36a5434fb.gif" alt="2\sqrt{(xy+yz+zx)(ab+bc+ca)}\leq a(y+z)+b(z+x)+c(x+y)" /></span></span></p>
<p><span class="postbody"><span class="postbody">assume that     <img class="latex" style="vertical-align:-3px;" title="a\geq b \geq c" src="http://alt1.mathlinks.ro/latexrender/pictures/5/6/a/56a9a53cac60e119936e5698f2521bddcd6db90d.gif" alt="" />           and      <img class="latex" style="vertical-align:-4px;" title="x \geq y \geq z" src="http://alt2.mathlinks.ro/latexrender/pictures/f/a/a/faa644c8a343a89eb225e9d997556c5def0c98e1.gif" alt="" />, </span></span></p>
<p><span class="postbody"><span class="postbody">we get that <img class="latex" style="vertical-align:-3px;" title="x+y \geq x+z \geq y+z" src="http://alt1.mathlinks.ro/latexrender/pictures/1/b/f/1bf7e360875c37b32601c55ed8d2688be7da639b.gif" alt="" />   then by Chebychev,</span></span></p>
<p><span class="postbody"><span class="postbody"><img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/8/d/4/8d43eb64b5e67e7ad8f83534ddb83c774aa1428b.gif" alt="a(x+y)+b(y+z)+c(z+x)\geq \frac{2}{3}(a+b+c)" />     (*)</span></span></p>
<p><span class="postbody"><span class="postbody">and we have that, </span></span><span class="postbody"><span class="postbody"> <img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/c/3/4/c3410b41b3193daa576a5357cf74a31f315c91a4.gif" alt="xy+yz+zx\leq \frac{(x+y+z)^2}{3}=\frac{1}{3}" /></span></span></p>
<p><span class="postbody"><span class="postbody">and  <img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/0/d/8/0d8ba8499411daa4d3274d34fc5b53565d3d00b7.gif" alt="ab+bc+ca \leq \frac{(a+b+c)^2}{3}" />   then,</span></span></p>
<p><span class="postbody"><span class="postbody"><img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/f/9/4/f94eba38ff5c40878e70671259914aa21abf5f39.gif" alt="2\sqrt{(xy+yz+zx)(ab+bc+ca)}\leq \frac{2}{3}(a+b+c)" /> </span></span></p>
<p><span class="postbody"><span class="postbody">from (*) and (**) we deduct that,</span></span></p>
<p><span class="postbody"><span class="postbody"><img class="latex" style="vertical-align:-5px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/e/4/2/e428c22038f4d4b0602d7b25443413abc8ef7518.gif" alt="2\sqrt{(xy+yz+zx)(ab+bc+ca)} \leq a(x+y)+b(y+z)+c(z+x)" /></span></span></p>
<p><span class="postbody"><span class="postbody"><img class="latex" style="vertical-align:-5px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/d/0/1/d016b018ac8a642b9d263f537b8b4aab1e845041.gif" alt="\Leftrightarrow ax+by+cz+2\sqrt{(xy+yz+zx)(ab+bc+ca)} \leq a+b+c" /></span></span></p>
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		<title>Inequality 14</title>
		<link>http://mathsmaster.wordpress.com/2009/04/07/inequality-14/</link>
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		<pubDate>Tue, 07 Apr 2009 14:51:25 +0000</pubDate>
		<dc:creator>mathsmaster</dc:creator>
				<category><![CDATA[Inégalités]]></category>

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		<description><![CDATA[Problem: let   such as  , find the maximum of:                                             Solution: first we remarque that, put that,   and    therefore we have            thus,   then  equality holds when ,<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=mathsmaster.wordpress.com&amp;blog=6029773&amp;post=136&amp;subd=mathsmaster&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Problem:</strong> let <span class="postbody"><img class="latex" style="vertical-align:-4px;" title="x,y,z \in\mathbb{R}" src="http://alt2.mathlinks.ro/latexrender/pictures/c/4/6/c466f494ddb03dc5dacd87058c101076eb2d0995.gif" alt="" />  such as  <img class="latex" style="vertical-align:-4px;" title="x^2+y^2+z^2=1" src="http://alt1.mathlinks.ro/latexrender/pictures/3/2/5/32534ff9358b647b86dfafa2b8fb7b87af44d8bf.gif" alt="" />, find the maximum of: </span><span class="postbody">                                            <img class="latex" style="vertical-align:-3px;" title="T=x^3+y^3+z^3-3xyz" src="http://alt1.mathlinks.ro/latexrender/pictures/4/2/9/429fa496c82d070e9bf8a1b8855790da202adb3b.gif" alt="" /></span></p>
<p><span class="postbody"><strong>Solution: </strong>first we remarque that,</span></p>
<p><span class="postbody"><img class="latex" style="vertical-align:-4px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/4/c/8/4c85593c9a4a800aed7e464d0fd93534d5789c98.gif" alt="T=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)" /></span></p>
<p><span class="postbody">put that, <img class="latex" style="vertical-align:-4px;" title="p=x+y+z" src="http://alt1.mathlinks.ro/latexrender/pictures/2/f/e/2fea53b47bc73cdac1b43fd955b4473c1aeaf695.gif" alt="" />  and  <img class="latex" style="vertical-align:-4px;" title="q=xy+yz+zx" src="http://alt2.mathlinks.ro/latexrender/pictures/b/1/6/b16d1dea41e22a7d4d05a0f4f8a3e7e9642a2d6e.gif" alt="" />  therefore <img class="latex" style="vertical-align:-4px;" title="T=p(1-q)" src="http://alt2.mathlinks.ro/latexrender/pictures/d/0/4/d0417a9166fd74fec2e4a03a6c378b07e1da87bb.gif" alt="" /></span></p>
<p><span class="postbody">we have          <img class="latex" style="vertical-align:-3px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/b/4/2/b422008ea9e157d8973801c79a7871c484a2ccde.gif" alt="2p\leq p^2+1=2+2q \Leftrightarrow p\leq q+1" /> </span></p>
<p><span class="postbody">thus, <img class="latex" style="vertical-align:-4px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/a/f/d/afde80853faacd6f6ebaac9e6b8249a2d37b8404.gif" alt="p(1-q)\leq (1-q)(1+q)=1-q^2\leq 1" /> </span></p>
<p><span class="postbody">then <img class="latex" style="vertical-align:-2px;" title="T_{max}=1" src="http://alt2.mathlinks.ro/latexrender/pictures/c/9/6/c96f33243c011e8880bdc40de5b005269403c2ae.gif" alt="" /> equality holds when <img class="latex" style="vertical-align:-1px;" title="x=1" src="http://alt1.mathlinks.ro/latexrender/pictures/7/c/a/7caf6056913504f0508c65faf2dc3f94ff65bcfd.gif" alt="" /> , <img class="latex" style="vertical-align:-4px;" title="y=z=0" src="http://alt2.mathlinks.ro/latexrender/pictures/e/0/b/e0b408e27de6368043b5187da5bb1acc13f43f3a.gif" alt="" /></span></p>
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			<media:title type="html">mathsmaster</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/c/4/6/c466f494ddb03dc5dacd87058c101076eb2d0995.gif" medium="image">
			<media:title type="html">x,y,z \in\mathbb{R}</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/3/2/5/32534ff9358b647b86dfafa2b8fb7b87af44d8bf.gif" medium="image">
			<media:title type="html">x^2+y^2+z^2=1</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/4/2/9/429fa496c82d070e9bf8a1b8855790da202adb3b.gif" medium="image">
			<media:title type="html">T=x^3+y^3+z^3-3xyz</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/4/c/8/4c85593c9a4a800aed7e464d0fd93534d5789c98.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/2/f/e/2fea53b47bc73cdac1b43fd955b4473c1aeaf695.gif" medium="image">
			<media:title type="html">p=x+y+z</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/b/1/6/b16d1dea41e22a7d4d05a0f4f8a3e7e9642a2d6e.gif" medium="image">
			<media:title type="html">q=xy+yz+zx</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/d/0/4/d0417a9166fd74fec2e4a03a6c378b07e1da87bb.gif" medium="image">
			<media:title type="html">T=p(1-q)</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/b/4/2/b422008ea9e157d8973801c79a7871c484a2ccde.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/a/f/d/afde80853faacd6f6ebaac9e6b8249a2d37b8404.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/c/9/6/c96f33243c011e8880bdc40de5b005269403c2ae.gif" medium="image">
			<media:title type="html">T_{max}=1</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/7/c/a/7caf6056913504f0508c65faf2dc3f94ff65bcfd.gif" medium="image">
			<media:title type="html">x=1</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/e/0/b/e0b408e27de6368043b5187da5bb1acc13f43f3a.gif" medium="image">
			<media:title type="html">y=z=0</media:title>
		</media:content>
	</item>
		<item>
		<title>Inequality 13</title>
		<link>http://mathsmaster.wordpress.com/2009/04/07/inequality-13/</link>
		<comments>http://mathsmaster.wordpress.com/2009/04/07/inequality-13/#comments</comments>
		<pubDate>Tue, 07 Apr 2009 14:25:09 +0000</pubDate>
		<dc:creator>mathsmaster</dc:creator>
				<category><![CDATA[Inégalités]]></category>

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		<description><![CDATA[Problem: if you know that the equation     has at least one reel root, prove that ,   Tournament of the Towns, 1993 Solution: let  be a root of the equation, therefore, by Cauchy-Schwarz,    and we have that,            then    <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=mathsmaster.wordpress.com&amp;blog=6029773&amp;post=134&amp;subd=mathsmaster&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Problem:</strong> if you know that the equation   <span class="postbody"><img class="latex" style="vertical-align:-1px;" title="x^4+ax^3+2x^2+bx+1=0" src="http://alt2.mathlinks.ro/latexrender/pictures/a/b/1/ab1448c00390129ec12dcea982e066d66b98fd99.gif" alt="" />  has at least one reel root, prove that , <img class="latex" style="vertical-align:-3px;" title="a^2+b^2\geq 8" src="http://alt1.mathlinks.ro/latexrender/pictures/7/d/1/7d1ae60f72071fb9d1749182fdd186a3fdac076d.gif" alt="" /> </span></p>
<p style="text-align:center;"><span class="postbody">Tournament of the Towns, 1993</span></p>
<p><span class="postbody"><strong>Solution: </strong>let <img class="latex" style="vertical-align:-1px;" title="x" src="http://alt1.mathlinks.ro/latexrender/pictures/1/1/f/11f6ad8ec52a2984abaafd7c3b516503785c2072.gif" alt="" /> be a root of the equation, therefore, by Cauchy-Schwarz,</span></p>
<p><span class="postbody"><img class="latex" style="vertical-align:-4px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/5/4/3/543805c26f8d4730388edbee8f847eceea0f70a4.gif" alt="(a^2+b^2)(x^6+x^2)\geq (ax^3+bx)^2=(x^2+1)^4" />   and we have that,</span></p>
<p><span class="postbody">        <img class="latex" style="vertical-align:-4px;" title="(x^2 -1)^4\geq 0" src="http://alt2.mathlinks.ro/latexrender/pictures/d/b/3/db3c1516473fdaa083ea939368742a685fb8bd9b.gif" alt="" />   <img class="latex" style="vertical-align:-4px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/d/6/0/d60c92bc5c106e0c962372c700e920f54300fffe.gif" alt="\Leftrightarrow x^8+6x^4+1\geq 4(x^6+x^2)" /></span></p>
<p><span class="postbody"><img class="latex" style="vertical-align:-4px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/f/c/0/fc03fbe4de72bc240bd4e3c6984053f1867b6874.gif" alt="\Leftrightarrow x^8+4x^6+6x^4+4x^2+1 \geq 8(x^6+x^2)" /><img class="latex" style="vertical-align:-4px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/b/f/1/bf1538f85c20175a6b994f35bb41848b41bf8b17.gif" alt="\Leftrightarrow (x^2+1)^4\geq 8(x^6+x^2)" /></span></p>
<p><span class="postbody">then    <span class="postbody"><img class="latex" style="vertical-align:-12px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/f/a/8/fa8cd2e0662bd92650386aaa1be9e3719bde684e.gif" alt="a^2+b^2\geq \frac{(x^2+1)^4}{x^6+x^2}\geq8" /></span></span></p>
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			<media:title type="html">mathsmaster</media:title>
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			<media:title type="html">x^4+ax^3+2x^2+bx+1=0</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/7/d/1/7d1ae60f72071fb9d1749182fdd186a3fdac076d.gif" medium="image">
			<media:title type="html">a^2+b^2\geq 8</media:title>
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			<media:title type="html">x</media:title>
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			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
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			<media:title type="html">(x^2 -1)^4\geq 0</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/d/6/0/d60c92bc5c106e0c962372c700e920f54300fffe.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
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			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
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			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

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			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>
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		<item>
		<title>Inequality 12</title>
		<link>http://mathsmaster.wordpress.com/2009/04/07/inequality-12/</link>
		<comments>http://mathsmaster.wordpress.com/2009/04/07/inequality-12/#comments</comments>
		<pubDate>Tue, 07 Apr 2009 13:35:41 +0000</pubDate>
		<dc:creator>mathsmaster</dc:creator>
				<category><![CDATA[Inégalités]]></category>

		<guid isPermaLink="false">http://mathsmaster.wordpress.com/?p=131</guid>
		<description><![CDATA[Probelm: let  be  positive reel numbers such as, , Prove that: Gazeta matematicã Solution: assume that,     therefore by Chebychev, Be Cauchy-Schwarz,     and also   , then     (*) By AM-GM,   and  then  (**) After summation of (*) and (**) we get,<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=mathsmaster.wordpress.com&amp;blog=6029773&amp;post=131&amp;subd=mathsmaster&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Probelm:</strong> let <img class="latex" style="vertical-align:-4px;" title="a,b,c" src="http://alt2.mathlinks.ro/latexrender/pictures/9/c/a/9caa91157421e243281346b0bf7a82b5200e67e2.gif" alt="" /> be  positive reel numbers such as, <span class="postbody"><img class="latex" style="vertical-align:-1px;" title="abc=1" src="http://alt2.mathlinks.ro/latexrender/pictures/d/7/6/d7609865020abbeddea362f6aa3fcacff5cd1c01.gif" alt="" />, Prove that:</span></p>
<p style="text-align:center;"><span class="postbody"><img class="latex aligncenter" style="vertical-align:-16px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/5/b/4/5b4467d90c990081717c09559d9f0c301881a994.gif" alt="\frac{b+c}{\sqrt{a}}+\frac{a+c}{\sqrt{b}}+\frac{b+a}{\sqrt{c}} \geq \sqrt{a}+\sqrt{b}+\sqrt{c}+3" /></span></p>
<p style="text-align:center;"><span class="postbody">Gazeta matematicã</span></p>
<p style="text-align:left;"><span class="postbody"><strong>Solution:</strong></span></p>
<p style="text-align:left;"><span class="postbody">assume that,   <span class="postbody"><img class="latex" style="vertical-align:-3px;" title="a \geq b \geq c" src="http://alt1.mathlinks.ro/latexrender/pictures/5/6/a/56a9a53cac60e119936e5698f2521bddcd6db90d.gif" alt="" />  therefore by Chebychev,</span></span></p>
<p style="text-align:left;"><span class="postbody"><span class="postbody"><img class="latex" style="vertical-align:-17px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/2/7/9/279692e3060ca2e396dde6582b72989b6c7610ca.gif" alt="S=\sum \frac{b+c}{\sqrt{a}} \geq \frac{2}{3}(a+b+c)\left(\frac{1}{\sqrt{a}}+\frac{1}{\sqrt{b}}+\frac{1}{\sqrt{c}}\right)" /></span></span></p>
<p style="text-align:left;"><span class="postbody"><span class="postbody">Be Cauchy-Schwarz,   </span></span><span class="postbody"><span class="postbody"> <img class="latex" style="vertical-align:-18px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/b/2/3/b23970504ea33b5322e415867821cd251780648f.gif" alt="\frac{1}{\sqrt{a}}+\frac{1}{\sqrt{b}}+\frac{1}{\sqrt{c}}\geq \frac{9}{\sqrt{a}+\sqrt{b}+\sqrt{c}}" /></span></span></p>
<p style="text-align:left;"><span class="postbody"><span class="postbody">and also   <img class="latex" style="vertical-align:-12px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/a/e/0/ae0f2230d703be83a10c120341a5c43720f42cfa.gif" alt="a+b+c\geq \frac{1}{3}\left(\sqrt{a}+\sqrt{b}+\sqrt{c}\right)^2" />, then</span></span></p>
<p style="text-align:left;"><span class="postbody"><span class="postbody"><img class="latex" style="vertical-align:-18px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/1/2/5/1253ecdc525a2213726ca500e8ffd8b9a2e711d6.gif" alt="S\geq \frac{2}{9}\left(\sqrt{a}+\sqrt{b}+\sqrt{c}\right)^2\right)\left( \frac{9}{\sqrt{a}+\sqrt{b}+\sqrt{c}}\right)=2\left(\sqrt{a}+\sqrt{b}+\sqrt{c}\right)" /></span></span></p>
<p style="text-align:left;"><span class="postbody"><span class="postbody"><img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/b/7/0/b70ea358a40d3f28d17d9076882494f9c5271820.gif" alt="\Leftrightarrow \frac{1}{2}S\geq \sqrt{a}+\sqrt{b}+\sqrt{c}" />    (*)</span></span></p>
<p style="text-align:left;"><span class="postbody"><span class="postbody">By AM-GM,   <img class="latex" style="vertical-align:-20px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/d/7/c/d7ce75f3eea93e108cc5387d215812e767fc396f.gif" alt="S=\sum \frac{b+c}{\sqrt{a}} \geq 3\sqrt[3]{\frac{(a+b)(b+c)(c+a)}{\sqrt{abc}}}" /></span></span></p>
<p style="text-align:left;"><span class="postbody"><span class="postbody">and <img class="latex" style="vertical-align:-4px;" title="(a+b)(b+c)(c+a)\geq 8abc=8" src="http://alt1.mathlinks.ro/latexrender/pictures/2/6/4/2645fc0fb90c264eb0218ca167210a6b289448fc.gif" alt="" /> then <img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/f/c/c/fccfff5c8449b0855eb509fc098169c671ee9adf.gif" alt="S\geq 6 \Leftrightarrow \frac{1}{2}S \geq 3" /> (**)</span></span></p>
<p style="text-align:left;"><span class="postbody"><span class="postbody">After summation of (*) and (**) we get,</span></span></p>
<p style="text-align:left;"><span class="postbody"><span class="postbody"><img class="latex" style="vertical-align:-16px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/5/b/4/5b4467d90c990081717c09559d9f0c301881a994.gif" alt="\frac{b+c}{\sqrt{a}}+\frac{a+c}{\sqrt{b}}+\frac{b+a}{\sqrt{c}} \geq \sqrt{a}+\sqrt{b}+\sqrt{c}+3" /></span></span></p>
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			<media:title type="html">a,b,c</media:title>
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			<media:title type="html">a \geq b \geq c</media:title>
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			<media:title type="html">(a+b)(b+c)(c+a)\geq 8abc=8</media:title>
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		<title>Inequality 11</title>
		<link>http://mathsmaster.wordpress.com/2009/04/07/inequality-11/</link>
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		<pubDate>Tue, 07 Apr 2009 13:11:48 +0000</pubDate>
		<dc:creator>mathsmaster</dc:creator>
				<category><![CDATA[Inégalités]]></category>

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		<description><![CDATA[Problem: let  , Prove that: Junior TST 2002,Romania Solution: Put that, , therefore, by AM-GM  and and we have,         if        then                 wich implies that,<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=mathsmaster.wordpress.com&amp;blog=6029773&amp;post=129&amp;subd=mathsmaster&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Problem:</strong> let <img class="latex" style="vertical-align:-5px;" title="a,b,c \in [0,1]" src="http://alt1.mathlinks.ro/latexrender/pictures/5/3/e/53ed4527a618b87fa246adf9fb4a74371c85d074.gif" alt="" /> , Prove that:</p>
<p style="text-align:center;"><img class="latex aligncenter" style="vertical-align:-5px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/c/a/3/ca39ab68cbb67a38df390d7eeb80491b9b66905f.gif" alt="\sqrt{abc}+\sqrt{(1-a)(1-b)(1-c)} &lt; 1" /></p>
<p style="text-align:center;">Junior TST 2002,Romania</p>
<p style="text-align:left;"><strong>Solution:</strong> Put that, <img class="latex" style="vertical-align:-2px;" title="x=a+b+c" src="http://alt1.mathlinks.ro/latexrender/pictures/6/3/1/631455dfc2862fad472603b3f5a41ea13d6e5fb0.gif" alt="" />, therefore, by AM-GM</p>
<p style="text-align:left;"><img class="latex" style="vertical-align:-12px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/e/5/b/e5b06cccdf632b61459a2b82f905d0b4fa462d4a.gif" alt="\sqrt{abc}\leq \left(\frac{x}{3}\right)^{\frac{3}{2}}" /> and <img class="latex" style="vertical-align:-17px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/8/f/a/8faa4e4f7b722d2b9a924332f4e7d75691ce38c7.gif" alt="\sqrt{(1-a)(1-b)(1-c)}\leq \left(\frac{3-x}{3}\right)^{\frac{3}{2}}" /></p>
<p style="text-align:left;">and we have,    <img class="latex" style="vertical-align:-4px;" title="n^a+m^a&lt; (n+m)^a" src="http://alt1.mathlinks.ro/latexrender/pictures/3/8/5/3855652aea7a95f0f49e3d7a37cb1986aad4f3cc.gif" alt="" />     if      <img class="latex" style="vertical-align:-1px;" title="a&gt;1" src="http://alt2.mathlinks.ro/latexrender/pictures/c/2/6/c26eea90be6d237b5fcf937a44ba499322dfd606.gif" alt="" /> </p>
<p style="text-align:left;">then              <img class="latex" style="vertical-align:-17px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/7/7/8/778b226e8cae2c265649020b3f4f519ca4e7e2a3.gif" alt="\left(\frac{x}{3}\right)^{\frac{3}{2}}+\left(\frac{3-x}{3}\right)^{\frac{3}{2}} &lt; \left(\frac{x+3-x}{3}\right)^{\frac{3}{2}}=1" />  </p>
<p style="text-align:left;">wich implies that, <img class="latex" style="vertical-align:-5px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/f/f/f/fff9dd457c1021330f5643b7e299512e0851f5d5.gif" alt="\sqrt{abc}+\sqrt{(1-a)(1-b)(1-c)}&lt;1" /></p>
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			<media:title type="html">x=a+b+c</media:title>
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			<media:title type="html">n^a+m^a&#60; (n+m)^a</media:title>
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			<media:title type="html">a&#62;1</media:title>
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		<item>
		<title>Inequality 10</title>
		<link>http://mathsmaster.wordpress.com/2009/04/07/inequality-10/</link>
		<comments>http://mathsmaster.wordpress.com/2009/04/07/inequality-10/#comments</comments>
		<pubDate>Tue, 07 Apr 2009 13:00:16 +0000</pubDate>
		<dc:creator>mathsmaster</dc:creator>
				<category><![CDATA[Inégalités]]></category>

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		<description><![CDATA[Problem: let  , prove that: Solution: Be Cauchy-Schwarz    then;     and   after summation we get;<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=mathsmaster.wordpress.com&amp;blog=6029773&amp;post=127&amp;subd=mathsmaster&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Problem: </strong>let <span class="postbody"><img class="latex" style="vertical-align:-4px;" title="a,b,c \in \mathbb{R}" src="http://alt1.mathlinks.ro/latexrender/pictures/5/9/f/59fe6ed8c3542af6adcdc3abb110d1209b3628ca.gif" alt="" /> , prove that:</span></p>
<p><span class="postbody"><img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/5/2/a/52a440e2c05f033c5d8937473027cfb38b780564.gif" alt="\sqrt{a^2+(1-b)^2}+\sqrt{b^2+(1-c)^2}+\sqrt{c^2+(1-a)^2}\geq \frac{3\sqrt{2}}{2}" /></span></p>
<p><span class="postbody"><strong></strong></span></p>
<p><span class="postbody"><strong>Solution: </strong>Be Cauchy-Schwarz <span class="postbody"><img class="latex" style="vertical-align:-4px;" title="2(x^2+y^2)\geq (x+y)^2" src="http://alt1.mathlinks.ro/latexrender/pictures/8/6/e/86e00e3bc084831c7ce0e0d9b5594b3b9587e0fd.gif" alt="" /></span></span></p>
<p><span class="postbody"><span class="postbody"><img class="latex" style="vertical-align:-16px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/0/a/7/0a7013ad895193caec810be3d7ff9a7c012565db.gif" alt="\Leftrightarrow \sqrt{x^2+y^2} \geq \frac{x+y}{\sqrt{2}}" />   then; <img class="latex" style="vertical-align:-16px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/f/8/1/f8143aa337d56db3e6dad958a7653e363020d01c.gif" alt="\sqrt{c^2+(1-a)^2}\geq \frac{1+c-a}{\sqrt{2}}" /></span></span></p>
<p><span class="postbody"><span class="postbody"><img class="latex" style="vertical-align:-16px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/e/1/6/e168566927a9253c87be6e7098159e1a5079ec45.gif" alt="\sqrt{a^2+(1-b)^2}\geq \frac{1+a-b}{\sqrt{2}}" />    and   </span></span><span class="postbody"><span class="postbody"><img class="latex" style="vertical-align:-16px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/2/a/8/2a823ae65ce5d33c254a578ee206082b48e2fd2c.gif" alt="\sqrt{b^2+(1-c)^2}\geq \frac{1+b-c}{\sqrt{2}}" /></span></span></p>
<p><span class="postbody"><span class="postbody">after summation we get;</span></span></p>
<p><span class="postbody"><span class="postbody"><img class="latex" style="vertical-align:-16px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/4/3/e/43ef2479b707196943277c280e25d80db32968d2.gif" alt="\sqrt{a^2+(1-b)^2}+\sqrt{b^2+(1-c)^2}+\sqrt{c^2+(1-a)^2}\geq \frac{3}{\sqrt{2}}=\frac{3\sqrt{2}}{2}" /></span></span></p>
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		<title>Problem 1</title>
		<link>http://mathsmaster.wordpress.com/2009/04/06/problem-1/</link>
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		<pubDate>Mon, 06 Apr 2009 20:05:44 +0000</pubDate>
		<dc:creator>mathsmaster</dc:creator>
				<category><![CDATA[Algèbre]]></category>

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		<description><![CDATA[Problem: Find all positive integers  such as    and  are all integers, Solution: Multiplying all equations we get is an integer.we have where is an integer suppose that one of is equal to for example then, is integer then is integer wich implies (*) is integer then is integer wich implies and from wich is false. [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=mathsmaster.wordpress.com&amp;blog=6029773&amp;post=124&amp;subd=mathsmaster&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Problem:</strong> Find all positive integers <img class="latex" style="vertical-align:-5px;" title="(a,b,c)" src="http://alt1.mathlinks.ro/latexrender/pictures/6/1/2/612d3f4a0fabf753d8b173ed9df00b267f704378.gif" alt="" /> such as</p>
<p> <img class="latex" style="vertical-align:-11px;" title="\frac{ab-1}{c},\frac{bc-1}{a}" src="http://alt1.mathlinks.ro/latexrender/pictures/7/b/3/7b33bb3ae66f786f439197f7c30d79f4cbcde9ee.gif" alt="" />  and <img class="latex" style="vertical-align:-11px;" title="\frac{ca-1}{b}" src="http://alt2.mathlinks.ro/latexrender/pictures/f/4/6/f465b25de344a54140704740d893319baad7fd88.gif" alt="" /> are all integers,</p>
<p><strong>Solution: </strong></p>
<p><img class="latex" style="vertical-align:-31px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/9/3/8/9384d833e340f9b4de39c6f20ff174e9aa0fe8cd.gif" alt="\begin{cases}\frac{ab-1}{c}=k\\ \frac{bc-1}{a}=l\\ \frac{ca-1}{b}=m\end{cases}" /></p>
<p>Multiplying all equations we get <img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/1/a/5/1a5fe7be5f5c7d9f5ad19f3335f90c5965e426a0.gif" alt="\frac{a^2b^2c^2-a^2bc-ab^2c-abc^2+ab+bc+ca-1}{abc}=klm" /><br />
<img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/8/3/8/83806a705f623d078d96ca269c22fa63a6fb1980.gif" alt="\frac{ab+bc+ca-1}{abc}=klm+a+b+c-abc" /></p>
<p><img class="latex" style="vertical-align:-11px;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/1/f/3/1f3fd21f631de74c4b68054a9829061ca7b5139f.gif" alt="\frac{1}{a}+\frac{1}{b}+\frac{1}{c}-\frac{1}{abc}" /> is an integer.we have <img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/1/0/b/10b27cc92457d9f0cabf33ecd30854f68a8d087f.gif" alt="\frac {1}{a} + \frac {1}{b} + \frac {1}{c} - \frac {1}{abc} = k" /> where <img class="latex" style="vertical-align:-1px;" title="k" src="http://alt1.mathlinks.ro/latexrender/pictures/1/3/f/13fbd79c3d390e5d6585a21e11ff5ec1970cff0c.gif" alt="" /> is an integer<br />
suppose that one of <img class="latex" style="vertical-align:-4px;" title="a,b,c" src="http://alt2.mathlinks.ro/latexrender/pictures/9/c/a/9caa91157421e243281346b0bf7a82b5200e67e2.gif" alt="" /> is equal to <img class="latex" style="vertical-align:0;" title="1" src="http://alt1.mathlinks.ro/latexrender/pictures/3/5/6/356a192b7913b04c54574d18c28d46e6395428ab.gif" alt="" /> for example <img class="latex" style="vertical-align:-1px;" title="c" src="http://alt1.mathlinks.ro/latexrender/pictures/8/4/a/84a516841ba77a5b4648de2cd0dfcb30ea46dbb4.gif" alt="" /> then,<br />
<img class="latex" style="vertical-align:-11px;" title="\frac {ac - 1}{b}" src="http://alt1.mathlinks.ro/latexrender/pictures/3/a/2/3a24533012d53e6f1fccf4a9d38884f65c4723a6.gif" alt="" /> is integer then <img class="latex" style="vertical-align:-11px;" title="\frac {a - 1}{b}" src="http://alt2.mathlinks.ro/latexrender/pictures/a/1/4/a148b27fe5aabef70de025257f9e1c02729a5497.gif" alt="" /> is integer wich implies <img class="latex" style="vertical-align:-3px;" title="b\leq a - 1" src="http://alt2.mathlinks.ro/latexrender/pictures/f/1/9/f19d3dbecb9f3cf78740e25ee2be18e3e89dac71.gif" alt="" /> (*)<br />
<img class="latex" style="vertical-align:-11px;" title="\frac {bc - 1}{a}" src="http://alt2.mathlinks.ro/latexrender/pictures/9/7/e/97e8cd586dc875e8e729a2e197ba94acd1025f00.gif" alt="" /> is integer then <img class="latex" style="vertical-align:-11px;" title="\frac {b - 1}{a}" src="http://alt1.mathlinks.ro/latexrender/pictures/3/1/f/31fa33648f9d8a27c125f8aa0ce92760e3f37360.gif" alt="" /> is integer wich implies <img class="latex" style="vertical-align:-3px;" title="a\leq b - 1" src="http://alt1.mathlinks.ro/latexrender/pictures/0/f/5/0f55e745b1b2adef1d6fe1418f132e4d1289d287.gif" alt="" /> and from <img class="latex" style="vertical-align:-3px;" title="a\leq b - 1 \leq a - 2" src="http://alt1.mathlinks.ro/latexrender/pictures/8/d/3/8d3c26d65e827947f1289dfb2971bda23a8dbf14.gif" alt="" /> wich is false. therefore <img class="latex" style="vertical-align:-4px;" title="a,b,c \geq 2" src="http://alt1.mathlinks.ro/latexrender/pictures/5/3/4/53458d023a9745222fd3a1182734ce8ca858262b.gif" alt="" /> thus<br />
<img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/4/e/e/4ee2396f29845c04725d1d0d892c30df492db2ff.gif" alt="k = \frac {1}{a} + \frac {1}{b} + \frac {1}{c} - \frac {1}{abc}\leq \frac {3}{2}" /> therefore <img class="latex" style="vertical-align:-1px;" title="k = 1" src="http://alt1.mathlinks.ro/latexrender/pictures/8/f/0/8f0dfd2fea8c9e59fd99b1fcb73bfa3d798fad0b.gif" alt="" /> or <img class="latex" style="vertical-align:-1px;" title="k = 0" src="http://alt1.mathlinks.ro/latexrender/pictures/1/a/b/1ab74059871c14599195cf4fc3c5c5dca2bc643d.gif" alt="" /><br />
if <img class="latex" style="vertical-align:-1px;" title="k = 0" src="http://alt1.mathlinks.ro/latexrender/pictures/1/a/b/1ab74059871c14599195cf4fc3c5c5dca2bc643d.gif" alt="" /> then <img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/7/b/3/7b37c64833af2b9c504dfefe16a29a414aff3565.gif" alt="\frac {1}{a} + \frac {1}{b} + \frac {1}{c} = \frac {1}{abc}" /><br />
<img class="latex" style="vertical-align:-1px;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/b/3/2/b3257dd11600d0cadb5e09aedb6754adcf2aed94.gif" alt="\Leftrightarrow ab + bc + ca = 1" /> wich is false, thus, <img class="latex" style="vertical-align:-1px;" title="k = 1" src="http://alt1.mathlinks.ro/latexrender/pictures/8/f/0/8f0dfd2fea8c9e59fd99b1fcb73bfa3d798fad0b.gif" alt="" /><br />
<img class="latex" style="vertical-align:-11px;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/c/e/6/ce619e15fb910372c3ac75be615b4afb30896222.gif" alt="\frac {1}{a} + \frac {1}{b} + \frac {1}{c} - \frac {1}{abc} = 1" /><br />
<img class="latex" style="vertical-align:-17px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/d/2/0/d207ee1558d75d1d9fbfa781da073f9a65dbac9b.gif" alt="\Leftrightarrow \frac {1}{bc}\left(\frac {bc - 1}{a} + b + c\right) = 1" /><br />
and we have <img class="latex" style="vertical-align:-3px;" title="a\geq 2" src="http://alt1.mathlinks.ro/latexrender/pictures/6/0/7/607f16dcb3f56ab23b0c11776b463dac9f4e718b.gif" alt="" /> therefore,<br />
<img class="latex" style="vertical-align:-17px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/3/f/a/3fa976d95e44b4daa038aef686ead515738d16e2.gif" alt="1 = \frac {1}{bc}\left(\frac {bc - 1}{a} + b + c\right)\leq \frac {1}{bc}\left(\frac {bc - 1}{2} + b + c\right)" /><br />
<img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/c/c/3/cc3b7b4b364502ce65ffb67cd419cf7262a31e5b.gif" alt="\Leftrightarrow bc \leq bc + 1 \leq 2(b + c) \Leftrightarrow \frac {1}{2} \leq \frac {1}{b} + \frac {1}{c}" /><br />
suppose that <img class="latex" style="vertical-align:-3px;" title="b\geq c" src="http://alt1.mathlinks.ro/latexrender/pictures/2/b/1/2b18fce1fa16938f29dbdd966cd3ec03c55afe0d.gif" alt="" /> therefore, <img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/5/9/1/5910be3300312854499d394c4f5d0f357a66cfd7.gif" alt="\frac {1}{2} \leq \frac {1}{b} + \frac {1}{c}\leq \frac {2}{c} \Leftrightarrow 2\leq c\leq 4" /><br />
if <img class="latex" style="vertical-align:-1px;" title="c = 4" src="http://alt1.mathlinks.ro/latexrender/pictures/5/5/4/5541914646e2f21de32679cee249e85bdd6b4572.gif" alt="" /> then, <img class="latex" style="vertical-align:-12px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/9/1/d/91ded24098bacf12c9e6dc1c116aa7caf2d0e967.gif" alt="\frac {1}{a} + \frac {1}{b} - \frac {1}{4ab} = \frac {3}{4}" /><br />
<img class="latex" style="vertical-align:-4px;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/e/4/4/e44d5a3902d1f0ce091e509296a0b0e0caf5da11.gif" alt="\Leftrightarrow (3b - 4)(3a - 4) = 13" /> wich don&#8217;t have any integer solution.<br />
the <img class="latex" style="vertical-align:-1px;" title="c = 2" src="http://alt1.mathlinks.ro/latexrender/pictures/5/8/2/58247fee3e062769a7b7bf9c3888e04e9104c9d6.gif" alt="" /> or <img class="latex" style="vertical-align:-1px;" title="c = 3" src="http://alt1.mathlinks.ro/latexrender/pictures/5/8/7/587fb0ba9dec79b8538a79c064a959fb12acc188.gif" alt="" /><br />
if <img class="latex" style="vertical-align:-1px;" title="c = 2" src="http://alt1.mathlinks.ro/latexrender/pictures/5/8/2/58247fee3e062769a7b7bf9c3888e04e9104c9d6.gif" alt="" /><br />
<img class="latex" style="vertical-align:-11px;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/2/a/a/2aae27d8b38ca0610ee493e94a52e9a9bd31e25f.gif" alt="\frac {1}{a} + \frac {1}{b} - \frac {1}{2ab} = \frac {1}{2}" /><br />
<img class="latex" style="vertical-align:-4px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/5/f/3/5f3f983433f5f983d0e26582536acc7037edaced.gif" alt="\Leftrightarrow (b - 2)(a - 2) = 3" /><br />
then <img class="latex" style="vertical-align:-4px;" title="S = \{2,3,5\}" src="http://alt1.mathlinks.ro/latexrender/pictures/5/4/7/5476d7ab0eb7657ccceaa4d450226b0ef4ddf60c.gif" alt="" /><br />
if <img class="latex" style="vertical-align:-1px;" title="c = 3" src="http://alt1.mathlinks.ro/latexrender/pictures/5/8/7/587fb0ba9dec79b8538a79c064a959fb12acc188.gif" alt="" /><br />
<img class="latex" style="vertical-align:-11px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/9/f/4/9f4a9f539e97703d58ddab13e2efc31f635e2bf2.gif" alt="\frac {1}{a} + \frac {1}{b} - \frac {1}{3ab} = \frac {2}{3}" /><br />
<img class="latex" style="vertical-align:-4px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/7/7/a/77ac0e854ba7b2ced6bd9045ffa679ecd97d6705.gif" alt="\Leftrightarrow (2b - 3)(2a - 3) = 7" /><br />
then <img class="latex" style="vertical-align:-4px;" title="S = \{2,3,5\}" src="http://alt1.mathlinks.ro/latexrender/pictures/5/4/7/5476d7ab0eb7657ccceaa4d450226b0ef4ddf60c.gif" alt="" /><br />
finally the only solution for the problem is ,<img class="latex" style="vertical-align:-4px;" title="S = \{2,3,5\}" src="http://alt1.mathlinks.ro/latexrender/pictures/5/4/7/5476d7ab0eb7657ccceaa4d450226b0ef4ddf60c.gif" alt="" /> with all permutation possible.</p>
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			<media:title type="html">mathsmaster</media:title>
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			<media:title type="html">(a,b,c)</media:title>
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			<media:title type="html">\frac{ab-1}{c},\frac{bc-1}{a}</media:title>
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			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/1/a/5/1a5fe7be5f5c7d9f5ad19f3335f90c5965e426a0.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/8/3/8/83806a705f623d078d96ca269c22fa63a6fb1980.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/1/f/3/1f3fd21f631de74c4b68054a9829061ca7b5139f.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/1/0/b/10b27cc92457d9f0cabf33ecd30854f68a8d087f.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/1/3/f/13fbd79c3d390e5d6585a21e11ff5ec1970cff0c.gif" medium="image">
			<media:title type="html">k</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/9/c/a/9caa91157421e243281346b0bf7a82b5200e67e2.gif" medium="image">
			<media:title type="html">a,b,c</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/3/5/6/356a192b7913b04c54574d18c28d46e6395428ab.gif" medium="image">
			<media:title type="html">1</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/8/4/a/84a516841ba77a5b4648de2cd0dfcb30ea46dbb4.gif" medium="image">
			<media:title type="html">c</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/3/a/2/3a24533012d53e6f1fccf4a9d38884f65c4723a6.gif" medium="image">
			<media:title type="html">\frac {ac - 1}{b}</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/a/1/4/a148b27fe5aabef70de025257f9e1c02729a5497.gif" medium="image">
			<media:title type="html">\frac {a - 1}{b}</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/f/1/9/f19d3dbecb9f3cf78740e25ee2be18e3e89dac71.gif" medium="image">
			<media:title type="html">b\leq a - 1</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/9/7/e/97e8cd586dc875e8e729a2e197ba94acd1025f00.gif" medium="image">
			<media:title type="html">\frac {bc - 1}{a}</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/3/1/f/31fa33648f9d8a27c125f8aa0ce92760e3f37360.gif" medium="image">
			<media:title type="html">\frac {b - 1}{a}</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/0/f/5/0f55e745b1b2adef1d6fe1418f132e4d1289d287.gif" medium="image">
			<media:title type="html">a\leq b - 1</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/8/d/3/8d3c26d65e827947f1289dfb2971bda23a8dbf14.gif" medium="image">
			<media:title type="html">a\leq b - 1 \leq a - 2</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/5/3/4/53458d023a9745222fd3a1182734ce8ca858262b.gif" medium="image">
			<media:title type="html">a,b,c \geq 2</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/4/e/e/4ee2396f29845c04725d1d0d892c30df492db2ff.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/8/f/0/8f0dfd2fea8c9e59fd99b1fcb73bfa3d798fad0b.gif" medium="image">
			<media:title type="html">k = 1</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/1/a/b/1ab74059871c14599195cf4fc3c5c5dca2bc643d.gif" medium="image">
			<media:title type="html">k = 0</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/1/a/b/1ab74059871c14599195cf4fc3c5c5dca2bc643d.gif" medium="image">
			<media:title type="html">k = 0</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/7/b/3/7b37c64833af2b9c504dfefe16a29a414aff3565.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/b/3/2/b3257dd11600d0cadb5e09aedb6754adcf2aed94.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/8/f/0/8f0dfd2fea8c9e59fd99b1fcb73bfa3d798fad0b.gif" medium="image">
			<media:title type="html">k = 1</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/c/e/6/ce619e15fb910372c3ac75be615b4afb30896222.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/d/2/0/d207ee1558d75d1d9fbfa781da073f9a65dbac9b.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/6/0/7/607f16dcb3f56ab23b0c11776b463dac9f4e718b.gif" medium="image">
			<media:title type="html">a\geq 2</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/3/f/a/3fa976d95e44b4daa038aef686ead515738d16e2.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/c/c/3/cc3b7b4b364502ce65ffb67cd419cf7262a31e5b.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/2/b/1/2b18fce1fa16938f29dbdd966cd3ec03c55afe0d.gif" medium="image">
			<media:title type="html">b\geq c</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/5/9/1/5910be3300312854499d394c4f5d0f357a66cfd7.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/5/5/4/5541914646e2f21de32679cee249e85bdd6b4572.gif" medium="image">
			<media:title type="html">c = 4</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/9/1/d/91ded24098bacf12c9e6dc1c116aa7caf2d0e967.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/e/4/4/e44d5a3902d1f0ce091e509296a0b0e0caf5da11.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/5/8/2/58247fee3e062769a7b7bf9c3888e04e9104c9d6.gif" medium="image">
			<media:title type="html">c = 2</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/5/8/7/587fb0ba9dec79b8538a79c064a959fb12acc188.gif" medium="image">
			<media:title type="html">c = 3</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/5/8/2/58247fee3e062769a7b7bf9c3888e04e9104c9d6.gif" medium="image">
			<media:title type="html">c = 2</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/2/a/a/2aae27d8b38ca0610ee493e94a52e9a9bd31e25f.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/5/f/3/5f3f983433f5f983d0e26582536acc7037edaced.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/5/4/7/5476d7ab0eb7657ccceaa4d450226b0ef4ddf60c.gif" medium="image">
			<media:title type="html">S = \{2,3,5\}</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/5/8/7/587fb0ba9dec79b8538a79c064a959fb12acc188.gif" medium="image">
			<media:title type="html">c = 3</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/9/f/4/9f4a9f539e97703d58ddab13e2efc31f635e2bf2.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/7/7/a/77ac0e854ba7b2ced6bd9045ffa679ecd97d6705.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/5/4/7/5476d7ab0eb7657ccceaa4d450226b0ef4ddf60c.gif" medium="image">
			<media:title type="html">S = \{2,3,5\}</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/5/4/7/5476d7ab0eb7657ccceaa4d450226b0ef4ddf60c.gif" medium="image">
			<media:title type="html">S = \{2,3,5\}</media:title>
		</media:content>
	</item>
		<item>
		<title>inequality 9</title>
		<link>http://mathsmaster.wordpress.com/2009/03/13/inequality-9/</link>
		<comments>http://mathsmaster.wordpress.com/2009/03/13/inequality-9/#comments</comments>
		<pubDate>Fri, 13 Mar 2009 12:02:40 +0000</pubDate>
		<dc:creator>mathsmaster</dc:creator>
				<category><![CDATA[Inégalités]]></category>

		<guid isPermaLink="false">http://mathsmaster.wordpress.com/?p=120</guid>
		<description><![CDATA[Problem: let , such as  prove that: Solution:  let put and and then the inequality becomes; with . We have because then By Shur, then by AM-GM therefore:<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=mathsmaster.wordpress.com&amp;blog=6029773&amp;post=120&amp;subd=mathsmaster&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Problem: </strong>let<strong> </strong><span class="postbody"><strong><img class="latex" style="vertical-align:-3px;" title="a,b,c \in \mathbb{R^{+*}}" src="http://alt2.mathlinks.ro/latexrender/pictures/f/c/d/fcdb2141053dd683cf7f4272776bdf8b6a3378e5.gif" alt="" /></strong>, such as <span class="postbody"><img class="latex" style="vertical-align:-2px;" title="a+b+c=3" src="http://alt2.mathlinks.ro/latexrender/pictures/c/8/b/c8b3bfb5fc903c9b035366e294a217c341c264dc.gif" alt="" /></span> prove that:<br />
</span></p>
<p style="text-align:center;"><strong><span class="postbody"><img class="latex aligncenter" style="vertical-align:-12px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/2/0/8/208c8f5ad2702dea6f1ce401b3665eaa30893314.gif" alt="4(ab+bc+ca) +\frac{a^2b^2}{a+b}+\frac{a^2c^2}{a+c}+\frac{b^2c^2}{b+c} \leq \frac{27}{2}" /></span></strong></p>
<p><strong>Solution:  </strong>let put <img class="latex" style="vertical-align:-1px;" title="a=3x" src="http://alt2.mathlinks.ro/latexrender/pictures/b/b/2/bb2d518afc88ce6378353adadebd4a5834713f3b.gif" alt="" /> and <img class="latex" style="vertical-align:-3px;" title="b=3y" src="http://alt1.mathlinks.ro/latexrender/pictures/5/d/b/5dbca5a42fb29f3484b531f40cff91fac7732bff.gif" alt="" /> and <img class="latex" style="vertical-align:0;" title="c=3z" src="http://alt2.mathlinks.ro/latexrender/pictures/e/3/d/e3d93b9c02a6e21d863afdc1c7201370181f7535.gif" alt="" /><br />
then the inequality becomes;<br />
<img class="latex" style="vertical-align:-14px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/1/1/8/118197d9c0f5c84217604711ffd81f207b9414ed.gif" alt="S=4\sum xy +3\sum \frac{x^2y^2}{x+y} \leq \frac{3}{2}" /> with <img class="latex" style="vertical-align:-4px;" title="x+y+z=1" src="http://alt1.mathlinks.ro/latexrender/pictures/7/0/b/70bd89f5cb028738daf11d0051c45b656f044c22.gif" alt="" />.<br />
We have <img class="latex" style="vertical-align:-14px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/0/4/2/042a73ebd1f3bef2669e9956808ffa031af7bf32.gif" alt="\frac{x^2y^2}{x+y} \leq \frac{xy(x+y)}{4}" /> because <img class="latex" style="vertical-align:-5px;" title="(x+y)^2 \geq 4xy" src="http://alt2.mathlinks.ro/latexrender/pictures/f/0/6/f060c788677b85de3eaf624a3f3b1347ef2de07c.gif" alt="" /><br />
then <img class="latex" style="vertical-align:-12px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/b/6/4/b646aec743f456ed07885cf662db84b8aec91243.gif" alt="S\leq 4\sum xy +\frac{3}{4}\left(\sum xy(x+y)\right) = 4\sum+\frac{3}{4}\left(\sum xy  -3xyz\right)" /><br />
<img class="latex" style="vertical-align:-12px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/6/9/5/695900abe2ea17da82ef60c99eeb7e6bb39bafcd.gif" alt="\Leftrightarrow S\leq \frac{19}{4}\left(\sum xy \right) - \frac{9xyz}{4}" /><br />
By Shur, <img class="latex" style="vertical-align:-12px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt1.mathlinks.ro/latexrender/pictures/6/6/3/6636ecc9749552ff15cc3f1333f9a7d573411a44.gif" alt="\sum xy \leq \frac{1+9xyz}{4} \Leftrightarrow \frac{19}{4}\left(\sum xy \right) \leq \frac{19+171xyz}{16}" /><br />
then <img class="latex" style="vertical-align:-12px;" title="S\leq \frac{19+135xyz}{16}" src="http://alt1.mathlinks.ro/latexrender/pictures/8/1/6/8164a744b78aaf56c996449f09db014ca9b6c224.gif" alt="" /> by AM-GM <img class="latex" style="vertical-align:-12px;" title="xyz \leq \frac{1}{27}" src="http://alt2.mathlinks.ro/latexrender/pictures/a/c/7/ac742817112bdabc4d2a19d2d882ce9d463c662b.gif" alt="" /> therefore:</p>
<p style="text-align:center;"><img class="latex   aligncenter" style="vertical-align:-12px;cursor:pointer;" title="Click on the formula to view the LaTeX code" src="http://alt2.mathlinks.ro/latexrender/pictures/e/a/9/ea9c9a0b5fecb1f3c1ececba7c4b960ffaa00f7d.gif" alt="S\leq \frac{19+\frac{135}{27}}{16}=\frac{3}{2}." /></p>
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			<media:title type="html">mathsmaster</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/f/c/d/fcdb2141053dd683cf7f4272776bdf8b6a3378e5.gif" medium="image">
			<media:title type="html">a,b,c \in \mathbb{R^{+*}}</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/c/8/b/c8b3bfb5fc903c9b035366e294a217c341c264dc.gif" medium="image">
			<media:title type="html">a+b+c=3</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/2/0/8/208c8f5ad2702dea6f1ce401b3665eaa30893314.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/b/b/2/bb2d518afc88ce6378353adadebd4a5834713f3b.gif" medium="image">
			<media:title type="html">a=3x</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/5/d/b/5dbca5a42fb29f3484b531f40cff91fac7732bff.gif" medium="image">
			<media:title type="html">b=3y</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/e/3/d/e3d93b9c02a6e21d863afdc1c7201370181f7535.gif" medium="image">
			<media:title type="html">c=3z</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/1/1/8/118197d9c0f5c84217604711ffd81f207b9414ed.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/7/0/b/70bd89f5cb028738daf11d0051c45b656f044c22.gif" medium="image">
			<media:title type="html">x+y+z=1</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/0/4/2/042a73ebd1f3bef2669e9956808ffa031af7bf32.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/f/0/6/f060c788677b85de3eaf624a3f3b1347ef2de07c.gif" medium="image">
			<media:title type="html">(x+y)^2 \geq 4xy</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/b/6/4/b646aec743f456ed07885cf662db84b8aec91243.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/6/9/5/695900abe2ea17da82ef60c99eeb7e6bb39bafcd.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/6/6/3/6636ecc9749552ff15cc3f1333f9a7d573411a44.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>

		<media:content url="http://alt1.mathlinks.ro/latexrender/pictures/8/1/6/8164a744b78aaf56c996449f09db014ca9b6c224.gif" medium="image">
			<media:title type="html">S\leq \frac{19+135xyz}{16}</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/a/c/7/ac742817112bdabc4d2a19d2d882ce9d463c662b.gif" medium="image">
			<media:title type="html">xyz \leq \frac{1}{27}</media:title>
		</media:content>

		<media:content url="http://alt2.mathlinks.ro/latexrender/pictures/e/a/9/ea9c9a0b5fecb1f3c1ececba7c4b960ffaa00f7d.gif" medium="image">
			<media:title type="html">Click on the formula to view the LaTeX code</media:title>
		</media:content>
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		<title>Inequality 8</title>
		<link>http://mathsmaster.wordpress.com/2009/03/04/inequality-8/</link>
		<comments>http://mathsmaster.wordpress.com/2009/03/04/inequality-8/#comments</comments>
		<pubDate>Wed, 04 Mar 2009 18:56:53 +0000</pubDate>
		<dc:creator>mathsmaster</dc:creator>
				<category><![CDATA[Inégalités]]></category>

		<guid isPermaLink="false">http://mathsmaster.wordpress.com/?p=116</guid>
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